A naturally occurring substance has the const | vedclass

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Question

(D) The molecule has $4$ chiral centers (marked with $*$ in the structure). It also has $2$ double bonds $(C=C)$ that can exhibit geometrical isomeris

Vedclass · Accepted Answer

$64$

Vedclass · Answer

(D) The molecule has $4$ chiral centers (marked with $*$ in the structure). It also has $2$ double bonds $(C=C)$ that can exhibit geometrical isomerism $(G.I.)$. Since the molecule is unsymmetrical,the total number of stereoisomers is given by $2^n$,where $n$ is the sum of chiral centers and double bonds capable of $G.I.$. Here,$n = 4 + 2 = 6$. Therefore,total stereoisomers $= 2^6 = 64$.

$A$ naturally occurring substance has the constitution shown below. How many stereoisomers may have this constitution?

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